Blank password for user account in windows 2000 server

29 Sep 2007 1:20 AM

slc

I'm trying to set up a user account in windows 2000 server without a
password.
When I try to add a new user without a password it says that the
password cannot be left blank. I have does this before, but can not
reminder the keys to type in that will allow for a blank password wile
making a new user account.

Thanks
For any help in advance.

29 Sep 2007 4:17 AM

Leonard Grey

Good question. How about asking in a Win2K server newsgroup?

---
Leonard Grey
Errare humanum est

s**@cfl.rr.com wrote:
Show quote

> I'm trying to set up a user account in windows 2000 server without a
> password.
> When I try to add a new user without a password it says that the
> password cannot be left blank. I have does this before, but can not
> reminder the keys to type in that will allow for a blank password wile
> making a new user account.
>
> Thanks
> For any help in advance.
>

29 Sep 2007 4:39 PM

Poprivet

s**@cfl.rr.com wrote:

> I'm trying to set up a user account in windows 2000 server without a
> password.
> When I try to add a new user without a password it says that the
> password cannot be left blank. I have does this before, but can not
> reminder the keys to type in that will allow for a blank password wile
> making a new user account.
>
> Thanks
> For any help in advance.

Don't look now, but this is an XP group, not a 2k group.

7 Oct 2007 4:49 PM

RajKohli

Maybe you need to configure the password policy "Minimum password length",
which in your case is not 0.
http://www.microsoft.com/technet/security/prodtech/windows2000/w2kccadm/acctpol/w2kadm07.mspx

Hope this help, let us know!

Show quote

"s**@cfl.rr.com" wrote:

> I'm trying to set up a user account in windows 2000 server without a
> password.
> When I try to add a new user without a password it says that the
> password cannot be left blank. I have does this before, but can not
> reminder the keys to type in that will allow for a blank password wile
> making a new user account.
>
> Thanks
> For any help in advance.
>
>